Saturday, 16 August 2014

`int_0^(pi/4)(sec^2 (t))dt` Evaluate the integral.

`int_0^(pi/4) sec^2(t) dt`


Take note that the derivative of tangent is d/(d theta) tan (theta)= sec^2 (theta).


So taking the integral of sec^2(t) result to:


`= tan (t) |_0^(pi/4)`


Plug-in the limits of integral as follows `F(x)=int_a^b f(x) dx= F(b)-F(a)` .


`=tan (pi/4)-tan(0)`


`=1-0`


`=1`


Therefore,  `int_0^(pi/4) sec^2(t) dt = 1` .

`int_0^(pi/4) sec^2(t) dt`


Take note that the derivative of tangent is d/(d theta) tan (theta)= sec^2 (theta).


So taking the integral of sec^2(t) result to:


`= tan (t) |_0^(pi/4)`


Plug-in the limits of integral as follows `F(x)=int_a^b f(x) dx= F(b)-F(a)` .


`=tan (pi/4)-tan(0)`


`=1-0`


`=1`


Therefore,  `int_0^(pi/4) sec^2(t) dt = 1` .

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