`27^(2/3) = 9` Write the exponential equation as a logarithmic equation or vice versa

Take note that if the exponential equation is in the form

`y=b^x`

its equivalent logarithmic form is

`x=log_b (y)`

Thus, converting

`27^(2/3)=9`

to logarithmic form, it becomes

`2/3=log_27 (9)`

Take note that if the exponential equation is in the form

`y=b^x`

its equivalent logarithmic form is

`x=log_b (y)`

Thus, converting

`27^(2/3)=9`

to logarithmic form, it becomes

`2/3=log_27 (9)`