Monday 2 March 2015

`int_(pi/4)^(pi/3) csc^2(theta) d theta` Evaluate the integral

You need to evaluate the definite integral using the fundamental theorem of calculus, such that:


`int_a^b f(u) du = F(b) - F(a)`


`int_(pi/4)^(pi/3) csc^2 theta d theta = int_(pi/4)^(pi/3) 1/(sin^2 theta) d theta = -cot theta|_(pi/4)^(pi/3)`


`int_(pi/4)^(pi/3) csc^2 theta d theta = -cot (pi/3) + cot (pi/4)`


`int_(pi/4)^(pi/3) csc^2 theta d theta = 1 - (sqrt3)/3 = (3 - sqrt3)/3`


Hence, evaluating the definite integral yields` int_(pi/4)^(pi/3) csc^2 theta d theta = (3 - sqrt3)/3.`

You need to evaluate the definite integral using the fundamental theorem of calculus, such that:


`int_a^b f(u) du = F(b) - F(a)`


`int_(pi/4)^(pi/3) csc^2 theta d theta = int_(pi/4)^(pi/3) 1/(sin^2 theta) d theta = -cot theta|_(pi/4)^(pi/3)`


`int_(pi/4)^(pi/3) csc^2 theta d theta = -cot (pi/3) + cot (pi/4)`


`int_(pi/4)^(pi/3) csc^2 theta d theta = 1 - (sqrt3)/3 = (3 - sqrt3)/3`


Hence, evaluating the definite integral yields` int_(pi/4)^(pi/3) csc^2 theta d theta = (3 - sqrt3)/3.`

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