Given ,
=>
now dividing with L on both sides we get
=>
=>
which is a linear differential equation of first order
Solve the differential equation for the current given a constant voltage
so
So , Re-writing the equation (1) as,
(1) => -----(2)
On comparing the above equation with the...
Given ,
=>
now dividing with L on both sides we get
=>
=>
which is a linear differential equation of first order
Solve the differential equation for the current given a constant voltage
so
So , Re-writing the equation (1) as,
(1) => -----(2)
On comparing the above equation with the general linear differential equation we get as follows
---- (3) -is the general linear differential equation form.
so on comparing the equations (2) and (3)
we get,
and
so , now
let us find the integrating factor
so now ,
=
=
So , now the general solution for linear differential equation is
=>
=> -----(4)
Now let us evaluate the part
this is of the form
and so we know it is equal to
=
so , now ,
where
so ,
now substituting in the equation (4) we get ,
upon cancelling and
, we get
so ,
is the solution
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