Sunday, 26 January 2014

Use the given differential equation for electrical circuits given by In this equation, I is the current, R is the resistance, L...

Given ,



=>


now dividing with L on both sides we get


=>


=>


which is a linear differential equation of first order


Solve the differential equation for the current given a constant voltage


so


So , Re-writing the equation (1) as,


(1) => -----(2)


On comparing the above equation with the...

Given ,



=>


now dividing with L on both sides we get


=>


=>


which is a linear differential equation of first order


Solve the differential equation for the current given a constant voltage


so


So , Re-writing the equation (1) as,


(1) => -----(2)


On comparing the above equation with the general linear differential equation we get as follows


---- (3)       -is the general linear differential equation form.


so on comparing the equations (2) and (3)


we get,


and


so , now


let us find the integrating factor



so now ,


=


=


So , now the general solution for linear differential equation is



=>


=> -----(4)


 Now let us evaluate the part



this is of the form


and so we know it is equal to


=


so , now ,



where


so ,



now substituting  in the   equation (4) we get ,





upon cancelling and   , we get



so ,


  is the solution

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