Saturday 16 August 2014

`int_0^(pi/4)(sec^2 (t))dt` Evaluate the integral.

`int_0^(pi/4) sec^2(t) dt`


Take note that the derivative of tangent is d/(d theta) tan (theta)= sec^2 (theta).


So taking the integral of sec^2(t) result to:


`= tan (t) |_0^(pi/4)`


Plug-in the limits of integral as follows `F(x)=int_a^b f(x) dx= F(b)-F(a)` .


`=tan (pi/4)-tan(0)`


`=1-0`


`=1`


Therefore,  `int_0^(pi/4) sec^2(t) dt = 1` .

`int_0^(pi/4) sec^2(t) dt`


Take note that the derivative of tangent is d/(d theta) tan (theta)= sec^2 (theta).


So taking the integral of sec^2(t) result to:


`= tan (t) |_0^(pi/4)`


Plug-in the limits of integral as follows `F(x)=int_a^b f(x) dx= F(b)-F(a)` .


`=tan (pi/4)-tan(0)`


`=1-0`


`=1`


Therefore,  `int_0^(pi/4) sec^2(t) dt = 1` .

No comments:

Post a Comment

In "By the Waters of Babylon," under the leadership of John, what do you think the Hill People will do with their society?

The best place to look for evidence in regards to what John's plans are for his people is the final paragraphs of the story. John has re...