Thursday, 1 January 2015

Find the particular solution that satisfies the given initial condition.

This differential equation can be solved by separating the variables.



Dividing by e^r and multiplying by ds results in the variables r and s on the different sides of the equation:



This is equivalent to



Now we can take the integral of the both sides of the equation:


 , where C is an arbitrary constant.


From here, 

This differential equation can be solved by separating the variables.



Dividing by e^r and multiplying by ds results in the variables r and s on the different sides of the equation:



This is equivalent to



Now we can take the integral of the both sides of the equation:


 , where C is an arbitrary constant.


From here, 


and 


or 


Since the initial condition is r(0) = 0, we can find the constant C:



This means 


and 


Plugging C in in the equation for r(s) above, we can get the particular solution:


 . This is algebraically equivalent to


 . This is the answer.

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