The Integral test says that this sum will converge if and only if this integral also converges: When integrating this, we would use integration by parts, and we would need to use it k times. The first set of parts is
The Integral test says that this sum will converge if and only if this integral also converges:
When integrating this, we would use integration by parts, and we would need to use it k times. The first set of parts is
Then we repeat for , and so on until we have only the
term left.
But the important thing is that the last term would only be in terms of a constant times , which clearly converges; and then all the other terms would look like this, for some integer
and some constant C:
The value of this term at we can simply calculate; no problem there, it will be some finite number. The limit as x goes to infinity we can also determine by the fact that
always increases faster than any polynomial as x gets very large, and thus for any value of p, this limit must be zero.
Thus, we have k-1 terms that are finite (zero minus a finite value), plus one final term that is a convergent integral. Therefore the whole integral converges; therefore the sum converges.
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