The range of arctan function is %7D%2C "(-pi/2, pi/2),")
on which interval tangent function is strictly monotone. Therefore we may take tangent on both sides, and the solution set will remain the same.
This gives %7D%7D%7D%3D-%7B%5Ctan%7B%7B%5Cleft(%7B1%7D%5Cright)%7D%7D%7D%2C "2x - 5 = tan(-1) = -tan(1),")
so the only solution is %7D%7D%7D%7D%7D%7B%7B2%7D%7D%5Capprox%7B1.72%7D. "x = (5 - tan(1))/2 approx 1.72.")
The range of arctan function is on which interval tangent function is strictly monotone. Therefore we may take tangent on both sides, and the solution set will remain the same.
This gives so the only solution is
No comments:
Post a Comment